A) 8 ´ 10-2 M
B) 8 ´ 10-11 M
C) 1.6 ´ 10-11 M
D) 8 ´ 10-5 M
Correct Answer: B
Solution :
CH3NH2 + HCl \[\xrightarrow{{}}\] \[C{{H}_{3}}NH_{3}^{+}C{{l}^{-}}\] 0.1 0.08 0 0.02 0 0.08 (Basic buffer solution) pOH = pKb + log \[\frac{0.08}{0.02}\] = pKb + 0.602 = 3.30 + 0.602= 3.902 \ pH = 10.09 [H+] = 7.99 ´ 10-11 » 8 ´ 10-11 MYou need to login to perform this action.
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