A) \[2.63\times {{10}^{-5}}\]
B) \[3.0\times {{10}^{-5}}\]
C) \[4.68\]
D) None of these
Correct Answer: A
Solution :
\[[{{H}^{+}}]=\text{Antilog}\,(-4.58)\]; \[[{{H}^{+}}]=2.63\times {{10}^{-5}}\,\,\,moles/litre\]You need to login to perform this action.
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