A) \[\sqrt{2}\]
B) \[1/\sqrt{2}\]
C) 2
D) \[1+\sqrt{2}\]
Correct Answer: A
Solution :
\[\frac{{{x}^{2}}}{25}-\frac{{{y}^{2}}}{25}=1\]. Eccentricity \[=\sqrt{2}\] as\[a=b\].
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