A) \[\frac{16}{3}\]
B) \[\frac{32}{3}\]
C) \[\frac{8}{3}\]
D) \[\frac{4}{3}\]
Correct Answer: B
Solution :
The given equation of hyperbola is \[16{{x}^{2}}-9{{y}^{2}}=144\]\[\Rightarrow \,\frac{{{x}^{2}}}{9}-\frac{{{y}^{2}}}{16}=1\] \ L.R. \[=\frac{2{{b}^{2}}}{a}\]=\[\frac{2.16}{3}=\frac{32}{3}\].You need to login to perform this action.
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