A) \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]
B) \[{{x}^{2}}+{{y}^{2}}={{b}^{2}}\]
C) \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}+{{b}^{2}}\]
D) \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}-{{b}^{2}}\]
Correct Answer: A
Solution :
The equation is\[{{(x-0)}^{2}}+{{(y-0)}^{2}}={{a}^{2}}\].You need to login to perform this action.
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