A) \[x{{\sec }^{2}}\theta -y{{\tan }^{2}}\theta =1\]
B) \[\frac{x}{a}\sec \theta -\frac{y}{b}\tan \theta =1\]
C) \[\frac{x+a\sec \theta }{{{a}^{2}}}-\frac{y+b\tan \theta }{{{b}^{2}}}=1\]
D) None of these
Correct Answer: B
Solution :
\[\frac{x(a\sec \theta )}{{{a}^{2}}}-\frac{y(b\tan \theta )}{{{b}^{2}}}=1\] Þ \[\frac{x}{a}\sec \theta -\frac{y}{b}\tan \theta =1\].You need to login to perform this action.
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