A) \[a-b\]
B) \[\sqrt{a-b}\]
C) \[\sqrt{{{a}^{2}}-{{b}^{2}}}\]
D) \[\sqrt{{{a}^{2}}+{{b}^{2}}}\]
Correct Answer: C
Solution :
Equation of director-circle of the hyperbola \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\]is \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}-{{b}^{2}}\] So, radius \[=\sqrt{{{a}^{2}}-{{b}^{2}}}\].You need to login to perform this action.
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