A) \[\frac{{{x}^{2}}}{12}-\frac{{{y}^{2}}}{4}=1\]
B) \[\frac{{{x}^{2}}}{4}-\frac{{{y}^{2}}}{12}=1\]
C) \[\frac{{{x}^{2}}}{8}-\frac{{{y}^{2}}}{2}=1\]
D) \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1\]
Correct Answer: B
Solution :
Distance between foci = 8 \ \[2ae=8\]also\[e=2\]; \ \[2a=4\] Þ \[a=2\] Þ \[{{a}^{2}}=4\]; \\[{{b}^{2}}=4(4-1)=12\] \ Equation of hyperbola is \[\frac{{{x}^{2}}}{4}-\frac{{{y}^{2}}}{12}=1\].
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