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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The equation of the transverse and conjugate axis of the hyperbola \[16{{x}^{2}}-{{y}^{2}}+64x+4y+44=0\] are

    A)            \[x=2,\ y+2=0\]                         

    B)            \[x=2,\ y=2\]

    C)            \[y=2,\ x+2=0\]                         

    D)            None of these

    Correct Answer: C

    Solution :

                       \[{{(4x+8)}^{2}}-{{(y-2)}^{2}}=-44+64-4\] Þ \[\frac{16{{(x+2)}^{2}}}{16}-\frac{{{(y-2)}^{2}}}{16}=1\] Transverse and conjugate axes are\[y=2\], \[x=-2\].


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