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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The locus of the point of intersection of the lines \[ax\sec \theta +by\tan \theta =a\] and \[ax\tan \theta +by\sec \theta =b\], where \[\theta \] is the parameter, is

    A)            A straight line                           

    B)            A circle

    C)            An ellipse                                  

    D)            A hyperbola

    Correct Answer: D

    Solution :

                       Squaring and subtracting, we get \[{{a}^{2}}{{x}^{2}}-{{b}^{2}}{{y}^{2}}={{a}^{2}}-{{b}^{2}}\], which is the equation of hyperbola.


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