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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The difference of the focal distance of any point on the hyperbola \[9{{x}^{2}}-16{{y}^{2}}=144\], is  [MP PET 1995; Orissa JEE 2004]

    A)            8     

    B)            7

    C)            6     

    D)            4

    Correct Answer: A

    Solution :

               The hyperbola is \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1.\]We have difference of focal distance \[=2a=8\].


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