JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The foci of the hyperbola \[2{{x}^{2}}-3{{y}^{2}}=5\], is  [MP PET 2000]

    A)            \[\left( \pm \frac{5}{\sqrt{6}},\ 0 \right)\]                                 

    B)            \[\left( \pm \frac{5}{6},\ 0 \right)\]

    C)            \[\left( \pm \frac{\sqrt{5}}{6},\ 0 \right)\]                                 

    D)            None of these

    Correct Answer: A

    Solution :

                       The given equation is \[2{{x}^{2}}-3{{y}^{2}}=5\]                    \[\Rightarrow \,\]\[\frac{{{x}^{2}}}{5/2}-\frac{{{y}^{2}}}{5/3}=1\]                    Now \[{{b}^{2}}={{a}^{2}}({{e}^{2}}-1)\]\[\Rightarrow \,\frac{5}{3}=\frac{5}{2}({{e}^{2}}-1)\] Þ \[e=\sqrt{\frac{5}{3}}\].                    The foci of hyperbola \[(\pm \,ae,\,0)\]                    \[=\left( \pm \sqrt{\frac{5}{2}}\,.\,\sqrt{\frac{5}{3}},0 \right)\]\[=\left( \pm \,\frac{5}{\sqrt{6}},0 \right)\].


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