A) \[y=3x\pm \sqrt{6}\]
B) \[y=6x\pm \sqrt{3}\]
C) \[y=x\pm \sqrt{6}\]
D) \[y=3x\pm 6\]
Correct Answer: A
Solution :
Tangent to \[\frac{{{x}^{2}}}{1}-\frac{{{y}^{2}}}{3}=1\] and perpendicular to \[x+3y-2=0\] is given by \[y=3x\pm \sqrt{9-3}=3x\pm \sqrt{6}\].You need to login to perform this action.
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