A) \[x+2=0\]
B) \[2x+1=0\]
C) \[x-2=0\]
D) \[x+y+1=0\]
Correct Answer: C
Solution :
Equation of the tangent to \[{{x}^{2}}-{{y}^{2}}-8x+2y+11=0\] at (2, 1) is \[2x-y-4(x+2)+\]\[(y+1)+11=0\] or \[x=2\].You need to login to perform this action.
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