A) \[\sqrt{3}x+2y=25\]
B) \[x+y=25\]
C) \[y+2x=25\]
D) \[2x+\sqrt{3}y=25\]
Correct Answer: D
Solution :
Applying the formula, the required normal is \[\frac{16x}{8}+\frac{9y}{3\sqrt{3}}=16+9\,\,i.e.,\]\[2x+\sqrt{3}y=25\] Trick : This is the only equation among the given options at which the point \[(8,\,3\sqrt{3})\] is located.You need to login to perform this action.
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