A) 3/4
B) 3/5
C) \[\sqrt{41}/4\]
D) \[\sqrt{41/5}\]
Correct Answer: C
Solution :
Equation of hyperbola is \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{25}=1\] Eccentricity is \[{{e}^{2}}=\frac{{{b}^{2}}}{{{a}^{2}}}+1\] i.e., \[{{e}^{2}}=\frac{25}{16}+1\] Þ \[{{e}^{2}}=\frac{41}{16}\] Þ \[e=\frac{\sqrt{41}}{4}\].You need to login to perform this action.
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