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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The latus-rectum of the hyperbola \[16{{x}^{2}}-9{{y}^{2}}=\] \[144\], is  [MP PET 2000]

    A)            \[\frac{16}{3}\]                         

    B)            \[\frac{32}{3}\]

    C)            \[\frac{8}{3}\]                           

    D)            \[\frac{4}{3}\]

    Correct Answer: B

    Solution :

                       The given equation of hyperbola is                    \[16{{x}^{2}}-9{{y}^{2}}=144\]\[\Rightarrow \,\frac{{{x}^{2}}}{9}-\frac{{{y}^{2}}}{16}=1\]                    \ L.R. \[=\frac{2{{b}^{2}}}{a}\]=\[\frac{2.16}{3}=\frac{32}{3}\].


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