A) \[(\pm 4,\ 0)\]
B) \[(0,\ \pm 4)\]
C) \[(\pm 5,\ 0)\]
D) \[(0,\ \pm 5)\]
Correct Answer: C
Solution :
The equation of hyperbola is \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1\] Now \[{{b}^{2}}={{a}^{2}}({{e}^{2}}-1)\]\[\Rightarrow \,e=\frac{5}{4}\] Hence foci are \[(\pm \,ae,\,0)\] Þ \[\left( \pm \,4.\frac{5}{4},\,0 \right)\] i.e., \[(\pm \,5,\,0)\].
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