A) \[x=9/\sqrt{13}\]
B) \[y=9/\sqrt{13}\]
C) \[x=6/\sqrt{13}\]
D) \[y=6/\sqrt{13}\]
Correct Answer: A
Solution :
Directrix of hyperbola \[x=\frac{a}{e}\], where \[e=\sqrt{\frac{{{b}^{2}}+{{a}^{2}}}{{{a}^{2}}}}=\frac{\sqrt{{{b}^{2}}+{{a}^{2}}}}{a}\] Directrix is, \[x=\frac{{{a}^{2}}}{\sqrt{{{a}^{2}}+{{b}^{2}}}}=\frac{9}{\sqrt{9+4}}\]Þ \[x=\frac{9}{13}\]
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