A) \[\sqrt{2}\]
B) 2
C) 3
D) \[\sqrt{3}\]
Correct Answer: D
Solution :
\[\frac{{{x}^{2}}}{(6/2)}-\frac{{{y}^{2}}}{6}=1\]Þ \[{{a}^{2}}=3\]and\[{{b}^{2}}=6\] Therefore\[e=\sqrt{\frac{{{b}^{2}}}{{{a}^{2}}}+1}\]Þ\[e=\sqrt{3}\].
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