A) \[\frac{2}{\sqrt{3}}\]
B) \[\frac{\sqrt{3}}{2}\]
C) \[\frac{2}{\sqrt{5}}\]
D) \[\frac{\sqrt{5}}{2}\]
Correct Answer: D
Solution :
Given conic is \[\frac{{{x}^{2}}}{{{(1)}^{2}}}-\frac{{{y}^{2}}}{{{\left( \frac{1}{2} \right)}^{2}}}=1\] \[\therefore {{b}^{2}}={{a}^{2}}({{e}^{2}}-1)\]Þ\[\frac{1}{4}+1={{e}^{2}}\]Þ \[e=\frac{\sqrt{5}}{2}\].You need to login to perform this action.
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