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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The auxiliary equation of circle of hyperbola \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\], is

    A)            \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]      

    B)            \[{{x}^{2}}+{{y}^{2}}={{b}^{2}}\]

    C)            \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}+{{b}^{2}}\]                                  

    D)            \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}-{{b}^{2}}\]

    Correct Answer: A

    Solution :

               The equation is\[{{(x-0)}^{2}}+{{(y-0)}^{2}}={{a}^{2}}\].


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