A) \[\frac{9}{4}\]
B) 9
C) \[\frac{3}{2}\]
D) \[\frac{9}{2}\]
Correct Answer: D
Solution :
\[9{{x}^{2}}-18x+9-16{{y}^{2}}-32y-16=144\] \[\Rightarrow \frac{{{(x-1)}^{2}}}{16}-\frac{{{(y+1)}^{2}}}{9}=1\] Þ Latus rectum \[=\frac{2{{b}^{2}}}{a}=\frac{2\times 9}{4}=\frac{9}{2}\].
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