A) 16
B) ?16
C) \[\pm 16\]
D) None of these
Correct Answer: C
Solution :
If \[y=2x+\lambda \] is tangent to given hyperabola, then \[\lambda =\pm \sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}}=\pm \sqrt{(100)\,(4)-144}=\pm \sqrt{256}=\pm 16\].
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