JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The equation of the tangent at the point \[(a\sec \theta ,\ b\tan \theta )\] of the conic \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\], is

    A)            \[x{{\sec }^{2}}\theta -y{{\tan }^{2}}\theta =1\]                        

    B)            \[\frac{x}{a}\sec \theta -\frac{y}{b}\tan \theta =1\]

    C)            \[\frac{x+a\sec \theta }{{{a}^{2}}}-\frac{y+b\tan \theta }{{{b}^{2}}}=1\]

    D)            None of these

    Correct Answer: B

    Solution :

               \[\frac{x(a\sec \theta )}{{{a}^{2}}}-\frac{y(b\tan \theta )}{{{b}^{2}}}=1\] Þ \[\frac{x}{a}\sec \theta -\frac{y}{b}\tan \theta =1\].


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