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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The equation of the tangents to the conic \[3{{x}^{2}}-{{y}^{2}}=3\] perpendicular to the line \[x+3y=2\] is

    A)            \[y=3x\pm \sqrt{6}\]                

    B)            \[y=6x\pm \sqrt{3}\]

    C)            \[y=x\pm \sqrt{6}\]                  

    D)            \[y=3x\pm 6\]

    Correct Answer: A

    Solution :

               Tangent to \[\frac{{{x}^{2}}}{1}-\frac{{{y}^{2}}}{3}=1\] and perpendicular to \[x+3y-2=0\] is given by \[y=3x\pm \sqrt{9-3}=3x\pm \sqrt{6}\].


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