2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Conic Sections

JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The equation of the tangent to the hyperbola \[4{{y}^{2}}={{x}^{2}}-1\] at the point (1, 0) is            [Karnataka CET 1994]

    A)            \[x=1\]                                      

    B)            \[y=1\]

    C)            \[y=4\]                                      

    D)            \[x=4\]

    Correct Answer: A

    Solution :

               The equation of the tangent to\[4{{y}^{2}}={{x}^{2}}-1\] at (1,0) is \[4(y\times 0)=x\times 1-1\]or \[x-1=0\]or\[x=1\].


You need to login to perform this action.
You will be redirected in 3 sec spinner