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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The equation of the tangent to the conic \[{{x}^{2}}-{{y}^{2}}-8x+2y+11=0\] at (2, 1) is     [Karnataka CET 1993]

    A)            \[x+2=0\]                                  

    B)            \[2x+1=0\]

    C)            \[x-2=0\]                                   

    D)            \[x+y+1=0\]

    Correct Answer: C

    Solution :

               Equation of the tangent to \[{{x}^{2}}-{{y}^{2}}-8x+2y+11=0\] at (2, 1) is \[2x-y-4(x+2)+\]\[(y+1)+11=0\] or \[x=2\].


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