A) \[{{x}^{2}}+{{y}^{2}}=16\]
B) \[{{x}^{2}}+{{y}^{2}}=4\]
C) \[{{x}^{2}}+{{y}^{2}}=20\]
D) \[{{x}^{2}}+{{y}^{2}}=12\]
Correct Answer: D
Solution :
Equation of ?director-circle? of hyperbola is\[{{x}^{2}}+{{y}^{2}}={{a}^{2}}-{{b}^{2}}\]. Here \[{{a}^{2}}=16,\,{{b}^{2}}=4\] \[\therefore \] \[{{x}^{2}}+{{y}^{2}}=\]12 is the required ?director circle?.
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