JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    Let E be the ellipse \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{4}=1\] and C be the circle\[{{x}^{2}}+{{y}^{2}}=9\]. Let P and Q be the points (1, 2) and      (2, 1) respectively. Then [IIT 1994]

    A)            Q lies inside C but outside E     

    B)            Q lies outside both C and E

    C)            P lies inside both C and E

    D)            P lies inside C but outside E

    Correct Answer: D

    Solution :

               The given ellipse is \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{4}=1\]. The value of the expression \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{4}-1\] is positive for \[x=1,\,y=2\] and negative for \[x=2,\,y=1\]. Therefore P lies outside E and Q lies inside E. The value of the expression \[{{x}^{2}}+{{y}^{2}}-9\]is negative for both the points P and Q. Therefore P and Q both lie inside C. Hence P lies inside C but outside E.


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