JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The length of the chord of the parabola \[{{y}^{2}}=4ax\] which passes through the vertex and makes an angle \[\theta \] with the axis of the parabola, is

    A)            \[4a\cos \theta \,\text{cose}{{\text{c}}^{2}}\,\theta \]             

    B)            \[4a{{\cos }^{2}}\theta \,\text{cosec}\,\theta \]

    C)            \[a\cos \theta \,\text{cose}{{\text{c}}^{2}}\,\theta \]

    D)            \[a{{\cos }^{2}}\theta \,\text{cosec}\,\theta \]

    Correct Answer: A

    Solution :

                      \[y=x\tan \theta \] will be equation of chord. The points of intersection of chord and parabola are            (0, 0), \[\left( \frac{4a}{{{\tan }^{2}}\theta },\ \frac{4a}{\tan \theta } \right)\]            Hence length of chord \[=4a\sqrt{{{\left( \frac{1}{{{\tan }^{2}}\theta } \right)}^{2}}+\frac{1}{{{\tan }^{2}}\theta }}\]                    \[=\frac{4a}{\tan \theta }\sqrt{\frac{1+{{\tan }^{2}}\theta }{{{\tan }^{2}}\theta }}=4a\text{ cose}{{\text{c}}^{2}}\theta \cos \theta \].


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