A) \[\frac{4}{49}{{x}^{2}}-\frac{196}{51}{{y}^{2}}=1\]
B) \[\frac{49}{4}{{x}^{2}}-\frac{51}{196}{{y}^{2}}=1\]
C) \[\frac{4}{49}{{x}^{2}}-\frac{51}{196}{{y}^{2}}=1\]
D) None of these
Correct Answer: C
Solution :
Trick: \[2a=7\] or \[a=\frac{7}{2}\] Also (5, ?2) satisfies it, so \[\frac{4}{49}(25)-\frac{51}{196}(4)=1\] and \[{{a}^{2}}=\frac{49}{4}\] Þ \[a=\frac{7}{2}\].
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