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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The equation of a hyperbola, whose foci are (5, 0) and (?5, 0) and the length of whose conjugate axis is 8, is

    A)            \[9{{x}^{2}}-16{{y}^{2}}=144\] 

    B)            \[16{{x}^{2}}-9{{y}^{2}}=144\]

    C)            \[9{{x}^{2}}+16{{y}^{2}}=144\] 

    D)            \[16{{x}^{2}}-9{{y}^{2}}=12\]

    Correct Answer: B

    Solution :

                      \[b=4\] Þ \[2ae=10\] Þ \[16=25-{{a}^{2}}\] Þ \[a=3\]                    Hence the hyperbola is \[16{{x}^{2}}-9{{y}^{2}}=144\].


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