JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The equation of the hyperbola referred to its axes as axes of coordinate and whose distance between the foci is 16 and eccentricity is \[\sqrt{2}\], is                                                                                                 [MNR 1984]

    A)            \[{{x}^{2}}-{{y}^{2}}=16\]         

    B)            \[{{x}^{2}}-{{y}^{2}}=32\]

    C)            \[{{x}^{2}}-2{{y}^{2}}=16\]       

    D)            \[{{y}^{2}}-{{x}^{2}}=16\]

    Correct Answer: B

    Solution :

                      \[2ae=16,\]\[e=\sqrt{2}\]Þ\[a=4\sqrt{2}\]and\[b=4\sqrt{2}\] \ equation is \[\frac{{{x}^{2}}}{{{(4\sqrt{2})}^{2}}}-\frac{{{y}^{2}}}{{{(4\sqrt{2})}^{2}}}=1\]         Þ \[{{x}^{2}}-{{y}^{2}}=32\].


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