A) 5/2
B) 2
C) 3/2
D) \[\sqrt{2}\]
Correct Answer: C
Solution :
Vertices \[(\pm 4,\,0)\equiv (\pm a,\,0)\] Þ \[a=4\] Foci \[(\pm 6,\,0)\equiv (\pm ae,\,0)\] Þ \[e=\frac{6}{4}=\frac{3}{2}\].
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