A) \[{{x}^{2}}-{{y}^{2}}=2\]
B) \[{{x}^{2}}-{{y}^{2}}=1\]
C) \[{{x}^{2}}-{{y}^{2}}=-1\]
D) None of these
Correct Answer: B
Solution :
Tangent at \[(a\sec \theta ,b\tan \theta )\] is, \[\frac{x}{(a/\sec \theta )}-\frac{y}{(b/\tan \theta )}=1\] or \[\frac{a}{\sec \theta }=1,\,\,\frac{b}{\tan \theta }=1\] Þ \[a=\sec \theta \], \[b=\tan \theta \]or \[(a,b)\]lies on \[{{x}^{2}}-{{y}^{2}}=1\].
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