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JEE Main & Advanced Mathematics Conic Sections Question Bank Hyperbola

  • question_answer
    The eccentricity of the hyperbola \[\frac{\sqrt{1999}}{3}({{x}^{2}}-{{y}^{2}})=1\] is [Karnataka CET 1999]

    A)            \[\sqrt{3}\]                               

    B)            \[\sqrt{2}\]

    C)            2     

    D)            \[2\sqrt{2}\]

    Correct Answer: B

    Solution :

               Here \[a=b,\] so it is a rectangular hyperbola. Hence, eccentricity\[e=\sqrt{2}\].


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