A) 179.2 L
B) 89.6 L
C) 44.8 L
D) 22.4 L
Correct Answer: A
Solution :
\[C+{{H}_{2}}O\to C{{O}_{\left( g \right)}}+{{H}_{2\left( g \right)}}\] \[12gm\to 1mol+1mol\] 12 gm C produces 2mole of gases (1mole CO & 1 mole of H2) \48 gm C may produce \[\frac{48}{12}\times 2=4\times 2=8mole\] \[=22.4\times 8\]L gases \[=179.2\] L gas.You need to login to perform this action.
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