A) \[x<2\]
B) x > 2
C) x >1
D) 1< x < 2
Correct Answer: D
Solution :
Function is monotonically decreasing, when \[{f}'(x)<0\] Þ \[6{{x}^{2}}-18x+12<0\] Þ \[{{x}^{2}}-3x+2<0\] Þ \[{{x}^{2}}-2x-x+2<0\] Þ \[(x-2)(x-1)<0\], \[\therefore x\in 1<x<2\].You need to login to perform this action.
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