A) ? 4
B) ? 3
C) ? 1
D) ? 2
Correct Answer: D
Solution :
To be increasing, \[\frac{d}{dx}({{x}^{2}}+kx+1)>0\]\[\Rightarrow 2x+k>0\] For \[x\in (1,\,2)\], the least value of \[k\]is ?2.You need to login to perform this action.
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