A) \[x\le -8,\,x\ge 2\]
B) \[x<-2,x\ge 8\]
C) \[x\le -2,x\ge 8\]
D) \[0\le x\le -2\]
Correct Answer: A
Solution :
\[f'(x)=6{{x}^{2}}+36x-96>0\], for increasing Þ \[f'(x)=(x+8)(x-2)\ge 0\]Þ\[x\ge 2,\ x\le -8\].
You need to login to perform this action.
You will be redirected in
3 sec
