A) \[(1,\,2e)\]
B) (0,e)
C) (2, 2e)
D) (1/e, 2e)
Correct Answer: B
Solution :
\[f(x)=\frac{\log x}{x}\] \[{f}'(x)=\frac{1}{{{x}^{2}}}-\frac{\log x}{{{x}^{2}}}=\frac{1-\log x}{{{x}^{2}}}\] For \[f(x)\] to be increasing, \[{f}'(x)>0\] Þ \[1-\log x>0\] Þ \[1>\log x\] Þ \[e>x\] \\[f(x)\] is increasing in the interval \[(0,\,e)\].You need to login to perform this action.
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