A) \[\frac{1}{2}<x<1\]
B) \[\frac{1}{2}<x<2\]
C) \[3<x<\frac{59}{4}\]
D) \[-\infty <x<\infty \]
Correct Answer: D
Solution :
\[{f}'\,(x)=6\,({{x}^{2}}-x+15)>0\,\forall \,x\].
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