A) Interval Function \[\left( -\infty ,\,\frac{1}{3} \right]\] \[3{{x}^{2}}-2x+1\]
B) (? ¥, ? 4] \[{{x}^{3}}+6{{x}^{2}}+6\]
C) (? ¥, ¥) \[{{x}^{3}}-3{{x}^{2}}+3x+3\]
D) [2, ¥) \[2{{x}^{3}}-3{{x}^{2}}-12x+6\]
Correct Answer: A
Solution :
\[f(x)=3{{x}^{2}}-2x+1\],\[{f}'(x)=6x-2\ge 0\] Þ \[x\ge \frac{1}{3}\] Option is incorrect. Checking other function similarly we find that they are correctly matched.
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