A) \[\text{12 }\!\!{}^\circ\!\!\text{ C}\]
B) \[\text{0 }\!\!{}^\circ\!\!\text{ }\]
C) \[\text{16 }\!\!{}^\circ\!\!\text{ C}\]
D) \[\text{14 }\!\!{}^\circ\!\!\text{ C}\]
Correct Answer: C
Solution :
\[\text{4}{}^\circ \text{C-}\left( \text{-12}{}^\circ \text{C} \right)\text{=4}{}^\circ \text{C+12}{}^\circ \text{C =16 }\!\!{}^\circ\!\!\text{ C}\]You need to login to perform this action.
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