A) \[\sin u\cos v\,[\cos (x+y-u-v)+i\sin (x+y-u-v)]\]
B) \[\sin u\cos v\,[\cos (x+y+u+v)+i\sin (x+y+u+v)]\]
C) \[\sin u\cos v\,[\cos (x+y+u+v)-i\sin (x+y+u+v)]\]
D) None of these
Correct Answer: A
Solution :
L.H.S. \[=\frac{(\cos x+i\sin x)(\cos y+i\sin y)}{(\cos u+i\sin u)(\cos v+i\sin v)}\]\[\sin u\cos v\] \[=\sin u\cos v[\cos (x+y-u-v)+i\sin (x+y-u-v)]\]You need to login to perform this action.
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