A) \[0+0i\]
B) \[-1-i\]
C) \[-1+i\]
D) None of these
Correct Answer: C
Solution :
If \[z=x+iy\] is the additive inverse of \[1-i\] then \[(x+iy)+(1-i)=0\] Þ \[x+1=0\], \[y-1=0\] Þ \[x=-1\], \[y=1\] \[\therefore \] The additive inverse of \[1-i\]is \[z=-1+i\] Trick: Since \[(1-i)+(-1+i)=0\]You need to login to perform this action.
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