A) \[2\sin {{e}^{\sqrt{x}}}\]
B) \[\sin {{e}^{\sqrt{x}}}\]
C) \[2\cos {{e}^{\sqrt{x}}}\]
D) \[-2\sin {{e}^{\sqrt{x}}}\]
Correct Answer: A
Solution :
Put \[{{e}^{\sqrt{x}}}=t\Rightarrow \frac{{{e}^{\sqrt{x}}}}{\sqrt{x}}=\,2dt\], (Now proceed yourself).You need to login to perform this action.
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