A) \[\sec (3x-5)+c\]
B) \[\frac{1}{3}\sec (3x-5)+c\]
C) \[\tan (3x-5)+c\]
D) None of these
Correct Answer: B
Solution :
Put \[t=3x-5\Rightarrow dt=3dx,\] therefore \[\int_{{}}^{{}}{\tan (3x-5)\,\sec (3x-5)\,dx}=\frac{1}{3}\int_{{}}^{{}}{\tan t.\sec t\,dt}\] \[=\frac{\sec t}{3}+c=\frac{\sec (3x-5)}{3}+c.\]You need to login to perform this action.
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