A) \[-\frac{1}{2}\cos \sqrt{x}+c\]
B) \[-2\cos \sqrt{x}+c\]
C) \[\frac{1}{2}\cos \sqrt{x}+c\]
D) \[2\cos \sqrt{x}+c\]
Correct Answer: B
Solution :
Put \[\sqrt{x}=t\Rightarrow \frac{1}{\sqrt{x}}\,dx=2dt,\] then it reduces to \[2\int_{{}}^{{}}{\sin t\,dt}=-2\cos t+c=-2\cos \sqrt{x}+c.\]You need to login to perform this action.
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